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An 8-uF capacitor is connected to a potential difference of 12 V. The potential energy is
(1 Point)
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Answer:
Potential energy= 576 x 10^-6 joules
Explanation:
potential energy= (1/2)CV²
P.E.= (1/2) x 8 x 10^-6 x 12 x12
= 576 x 10^-6 J
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