Question

16. An object is placed 15 cm in front of a convex lens. If focal length of the lens is 20 cm, find the
position and magnification of the image formed
pls solve its urgent ​

Answer 1

Answer:

hey mate ur answer is here

Explanation:

check the attachment below

MARK ME AS BRAINLIEST

Answer 2

$\sf{\large{\underline{\underline{EXPLANATION:}}}}$

$\sf{Given}\begin{cases}\sf{u=-15cm}\\ \sf{f=+20cm}\\ \sf{v=??}\end{cases}$

$\textbf{\underline{Using lens formula,,}}</p><p>$

$\mathtt{\boxed{\blue{\frac{1}{v}-\frac{1}{u}=\frac{1}{f}}}}$

$\sf{\implies{\frac{1}{v}-\frac{1}{(-15)}=\frac{1}{20}}}$

$\sf{\implies{\frac{1}{v}=\frac{1}{20}-\frac{1}{15}}}$

$\sf{\implies{\frac{1}{v}=\frac{3-4}{60}}}$

$\sf{\implies{\frac{1}{v}=\frac{-1}{60}}}$

$\sf{\implies{v=-60cm}}$

Since,,the value of v is -ve , therefore the image is formed in the side of object and at the distance of 60cm.(position)

$\textbf{\underline{To find magnification,,}}</p><p>$

$\mathtt{\boxed{\blue{m=\frac{v}{u}}}}$

$\sf{\implies{v=\cancel\dfrac{-60}{-15}}}$

$\sf{\implies{v=4}}$

Hence, the IMG is 4 times bigger than the object..

Hope it helps ❣️❣️❣️