Question

16 and 56 Find HCF of given set of numbers.by finding factors.

Answer 1

16 = 2× 2 × 2×2

56 = 2×2×2 ×7

2×2×2 is common there ,
hence ,.h.c.f = 2×2×2 =8

HOPE IT HELPS !
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Answer 2

Answer: 8

Step-by-step explanation:

Resolving prime factors of

16 and 56

16 = 2×2×2×2 = 2⁴

56 = 2×2×2×7 = 2³ × 7¹

HCF of 16 and 56 = product of

the smallest power of each

common prime factors of the

numbers

= 2³

= 8

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