Question

16. α, β, γ are zeroes of cubic polynomial kx3 – 5x + 9.

Ifα3 +β3 +γ3 =27,findthevalueofk.

Answer 1

Step-by-step explanation:

Alpha + Beta + Gama = -b/a = 0

We know that , Alpha + Beta + Gama = 0

So , Alpha³ + Beta³ + Gama³ =3Alpha*Beta*Gama

Alpha*Beta*Gama = -9/k

27 = 3(-9/k)

27 = -27/k

k = -1