Math, asked by tubaali2608, 2 months ago

16. At the time of house building a man takes a
loan of 20,000 at the rate of 15% simple
interest per annum and after 1 year at the
time of daughter's marriage he takes another
loan of? 15,000 from local cooperative at
the rate 12% simple interest. After 3 years
of daughter's marriage he got 56,000 as
retirement gratuity. If he repays both the loans
with interest then after repayment of loan
how much cash money will be left with him?​

Answers

Answered by lathpiyush
0

Answer: 3600

Step-by-step explanation: 20000*15*4/100

= 3000 (SI)*4= 12000

20000+12000= 32000

15000*12*3/100

150*36

= 5400

= 15000+5400

= 20400

= 32000+20400

= 52400

= 56000-52400

= 3600(Money left with him)

Similar questions