Question

16.Balance the reaction using Ion Electron method KMnO4+

SnCl2+ HCl------------ >MnCl2 +SnCl4 +KCl+H2O
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Answer 1

Answer:

Explanation:

HCl + KMnO4 → KCl + MnCl2 + H2O + Cl2

Answer 2

Answer:

2 KMnO4 + 5 SnCl2 + 16 HCl → 2 MnCl2 + 5 SnCl4 + 2 KCl + 8 H2O

Explanation:

This is an oxidation-reduction (redox) reaction:

2 MnVII + 10 e- → 2 MnII(reduction)

5 SnII - 10 e- → 5 SnIV(oxidation)

KMnO4 is an oxidizing agent, SnCl2 is a reducing agent.

hope it helpss