Question

16. Calculate Kinetic energy of 5 moles of Nitrogen at 27°C. 15 the structure Methanomolecule​

Answer 1

Answer:

use KE=3/2nRT

Explanation:

T should be K,so convert it to K..ie 27°+273=300K

so, KE=3/2 ×5×8.3×300

approximately it will be 18675 J..

pls verify ones..

Answer 2

Explanation:

Kinetic energy of the ideal gas can be calculated as

Kinetic energy = {3*n*R*T} / 2

where,

n = number of moles

R = gas constant

T = temperature in kelvin

We have above is, n = 5 moles of N

R = 8/314,

and T = 27 + 273 (to convert celsius to kelvin, add 273)=300.

Kinetic energy = {3*5*8.314*300} / 2

= 18,706.05 joules or 18.706 kj