16. Calculate the de-Broglie wavelength of an electron.
2
Answers
Answered by
1
Answer:
n=2
K.E energy of the second state is:
n
2
13.6
=
4
13.6
3.4×1.6×10
−19
j
de brogile wavelength
λ=
2mE
k
h
2×9.1×10
−31
×3.4×1.6×10
−19
6.63×10
−34
=0.67nm
Answered by
1
Answer:
6.63×10 −34 =0.67nm
Explanation:
n=2
K.E energy of the second state is:
13.6/n^2=13.6/4
= 3.4×1.6×10 −19 j
de brogile wavelength
λ= h/root2mEk
6.63×10 −34 =0.67nm
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