Question

16. Calculate the short and long wavelength limits of Lyman series in the specturm of hydrogen.​

Answer 1

Explanation:

Calculate the shortest and longest wavelengths in hydrogen spectrum of Lyman series.

For Lyman series, n1=1.

For shortest wavelength in Lyman series (i.e., series limit), the energy difference in two states showing transition should be maximum, i.e., n2=∞.

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