16. Calculate the standard entropy change of the following reaction at 298 K A+
298 K the standard molar entropies of Fe, O2 and Fe2O3 are 27.3, 205.0 and
87.4 J.K. mol-' respectively. 4 Fe(s) + 30260) —2Fe2O3(9)
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ΔrS° =∑ S° (Products) ∑S° (Reactants) = 2 S° (Fe2O3 ) – [4 S° (Fe) + 3 S° (O2 )]. = 2 × 87.4 – [4 × 27.3 + 3 × 205.0] J K–1 mol–1 = – 549.4 J K–1 mol–1. This is the entropy change of the reaction, i.e., system (ΔSsystem) ... 1648000 J mol–1 – 298 K × –549.4 J K–1 mol–1) ... 4Fe(s) + 302 (g) → 2Fe2O3(s).
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