Question

16. Calculate the uncertainty in the velocity of an electron if the uncertainty in its position is 1.0 x 10^10cm/s​

Answer 1

Answer:

Δv = 0.05854 × 10^-12 m/s

Explanation:

Given Δx = 1.0 x 10^10cm/s

= 1.0 × 10 ^8m/s

According to Heisenberg uncertainty principle

Δx × Δp = h/4π

Δx × Δv = h/4πm

1.0 × 10 ^8m/s × Δv = 6.626×10^-34/ 4×3.14×9.1×10 ^-31

1.0 × 10 ^8 × Δv= 6.626×10^-34 / 112.84 × 10 ^-31

1.0 × 10 ^8× Δv= 0.05854 × 10^-4

Δv = 0.05854 × 10^-4/1.0 × 10 ^8

Δv = 0.05854 × 10^-12 m/s

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