Question

16 cm
#
16 cm
10 cm
16 cm
35 cm
16 cm
10 cm
16 cm
#
16 cm find the area of polygon ​

Answer 1

Step-by-step explanation:

Clearly by observation we can see that the polygon is of two trapeziums of equal length and height....

Area of trapezium is given by,

$\frac{1}{2} \times height \times (sum \: of \: parallel \: sides)$

so as we already found in observation that the polygon is of two trapeziums of equal length and height.. area of the given polygon can be given by,

$2( \frac{1}{2} \times height \times (sum \: of \: parallel \: sides)$

By observation,

height is equal to 10 cm.... parallel side one is equal to 35 cm and parallel side two is equal to 16 cm...

By substituting the values, we get,

$2( \frac{1}{2} \times 10 \times (35 + 16)) \\ \\ = > 2(5)(51) = 51(10) = 510 \: {cm}^{2}$

Therefore area of the Polygon is equal to 510 CM square...

Mark as Brainliest....

Answer 2

Step-by-step explanation:

we can see that the polygon is of two trapeziums of equal length and height....

Area of trapezium is given by,

\frac{1}{2} \times height \times (sum \: of \: parallel \: sides)

2

1

×height×(sumofparallelsides)

so as we already found in observation that the polygon is of two trapeziums of equal length and height.. area of the given polygon can be given by,

2( \frac{1}{2} \times height \times (sum \: of \: parallel \: sides)2(

2

1

×height×(sumofparallelsides)

By observation,

height is equal to 10 cm.... parallel side one is equal to 35 cm and parallel side to see equal to 16 cm...

By substituting the values, we get,

\begin{gathered}2( \frac{1}{2} \times 10 \times (35 + 16)) \\ \\ = > 2(5)(51) = 51(10) = 510 \: {cm}^{2}\end{gathered}

2(

2

1

×10×(35+16))

=>2(5)(51)=51(10)=510cm

Therefore area of the Polygon is equal to 510 CM square...