Question

16. Convert a pressure of 1.033 x 104 kgfm-² into
centimetre of mercury column. Given density of
mercury is 13.6 gem and g = 980 cm s-²​

Answer 1

SI unit of density is Kg/m³

1 m = 100 cm => 1 cm = 10-² m

1 Kg = 1000g => 1g = 10-³ Kg

now,

13.6 g/cm³ = 13.6 × ( 10-³)/(10-²)³ Kg/m³

= 13.6 × 10-³/10^-6 Kg/m³

= 13.6 × 10^(-3 + 6) Kg/m³

= 13.6 × 10³ Kg/m³

｡◕‿◕｡

Answer 2

SI unit of density is Kg/m³

1 m = 100 cm => 1 cm = 10-² m

1 Kg = 1000g => 1g = 10-³ Kg

now,

13.6 g/cm³ = 13.6 × ( 10-³)/(10-²)³ Kg/m³

= 13.6 × 10-³/10^-6 Kg/m³

= 13.6 × 10^(-3 + 6) Kg/m³

= 13.6 × 10³ Kg/m³

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