Chemistry, asked by archanasrivastav264, 23 days ago

16. Correct order of solubility is : (1) BeSo, > MgSo. Caso, > Srso, > BaSO, (2) Beso, > Caso, > MgSo, > Srso, > Baso, (3) Baso, > Srso, MgSo, > Caso, > Beso (4) None of these​

Answers

Answered by mirtouseef350
0

Answer:

Correct option is A

Arrange the following compounds as decreasing order of their solubility:

BeSO 4 ,MgSO 4 ,CaSO 4 ,SrSO 4 ,BaSO 4

The solubility of sulphates in water decreases down the group. The magnitude of the lattice enthalpy remains almost constant as the sulphate ion is so big that small increase in the size of cation from Be Ba does not make any difference. The hydration enthalpy decreases from Be 2+ to Ba 2+

as the size of the cation increases down the group.

Hence the solubility of sulphates of alkaline earth metal decreases down the group mainly due to

Hence the solubility of sulphates of alkaline earth metal decreases down the group mainly due to decreasing hydration enthalpy from Be 2b to Ba 2+

. The high solubility of BeSO 4 and MgSO 4

is due to the high hydration enthalpy because of the smaller size of Be 2+ and Mg 2+

ions. The reason for this is because the sulphates of alkaline earth metals decompose on heating giving their corresponding oxides and SO 3.

The decreasing order of solubility would be-

BeSO 4 >MgSO 4 >CaSO 4 >SrSO 4 >BaSO 4 >RaSO 4

Hence, the correct option is A.

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