Question

16 coulamb distributed on a sphere of radius 2cm. Surface charge dencity of the surface is
$\frac{10 {}^{4} }{\pi}$
$\frac{10 {}^{3} }{\pi}$

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Answer 1

Answer:

=10^4/π

Explanation:

=q/s

q=16c. S=4πr^2

=16/4π×0.02×0.02

=10^4/π