Question

16. Divide 180 into two parts such that the first part is 12 less than twice the second part.​

Answer 1

Answer:

HERE IS THE ANSWER .

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let second part be y

So, the frist part will be = 2y-12 [ATQ]

Now, 2y-12+y = 180

or,3y = 192

or, y = 64

Therefore, the second part will be = 64

Hence, the first part will be = 2×64-12 = 128-12 = 116

We can cross check that 64 + 116 = 189

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