Question

16 Expansion of a perfect gas into vacuum is related with
q=0
(1) ∆H = 0
(4) All of these
w=0
plz explain one by one​

Answer 1

Explanation:

w=-p expantion (v2-v1) p expantion

=0 =0 vaccume

.•. w=0

net heat exchange with surrounding will be zero because surrounding is vaccum.

q=0

using 1st law if therom

delta u =q+w=0

delta u=0