Question

16. Express sec A in terms of sin A.​

Answer 1

Answer:

cosA = 1- sinA

Therefore, secA = 1/ 1 - sinA

Answer 2

Answer:

secA=1/cosA

secA=1/sin(90-A)

tanA=sinA/cosA

cosA=sin(90-A)

so,

tanA=sinA/sin(90-A)

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