16. Factorise:- (5x-3)^2 - (5x-3) - 20
Answers
Answered by
3
(5x-3)^2-(5x-3)-20
= (5x-3)^2-5(5x-3)+4(5x-3) - 20
= (5x-3)((5x-3)-5) + 4((5x-3)-5)
= ((5x-3)-5)((5x-3)+4)
= (5x-8)(5x+1)
Hope this helps you
Answered by
1
Answer:
let (5x-3)= a
a^2-a-20
a^2-5a+4a-20
a(a-5)+4(a-5)
(a-5)(a+4)
(5x-3-5)(5x-3+4)
(5x-8)(5x-1)
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