Question

16. Father's age is three times his son's age. Four years ago, he was 4 times his son's age. Find their present
ages,​

Answer 1

Answer:

let the son age be ×

father age =3××

four year ago

son =×-4

father=3×-×

Step-by-step explanation:

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Answer 2

Let present age of the son is x years.

Then the age of the father is 3x years.

Then according to the problem we get,

3x−4=4(x−4)

or, 4x−3x=16−4

x=12.

So the son's age is 12 years and that of the father is 12×3=36 years.