Question

16. Father's age is three times his son's age. Four years ago, he was 4 times his son's age. Find their present
ages​

Answer 1

Answer:

So the son's age is 12 years and that of the father is 12×3=36 years.

Step-by-step explanation:

Let present age of the son is x years.

Then the age of the father is 3x years.

Then according to the problem we get,

3x−4=4(x−4)

or, 4x−3x=16−4

x=12.

So the son's age is 12 years and that of the father is 12×3=36 years.

Answer 2

Answer

Let present age of the son is x years.

Then the age of the father is 3x years.

Then according to the problem we get,

3x−4=4(x−4) 

or, 4x−3x=16−4

x=12.

So the son's age is 12 years and that of the father is 12×3=36 years.

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