Math, asked by neelamruhela717, 3 months ago

16. Find the area of the isosceles triangle whose
(i) each of the equal sides is 8 cm and the base
is 9 cm;
(ii) each of the equal sides is 10 cm and the
base is 12 cm;
(iii) each of the equal sides is 7.4 cm and the
base is 6.2 cm;
(iv) perimeter is 11 cm and base is 4 cm.
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Answers

Answered by Souravsingh2318
4

Give me a brain least.

16. Find the area of the isosceles triangle whose :

(I) each of the equal sides is 8 cm and the base is 9 cm ;

= Area of Isosceles = 1/2×b×h.

= 1/2×9×8.

= [ 8 divide by 2 ] .

= 1×9×4.

= 36. Ans…

(ii) each of the equal sides is 10 cm and the base is 12 cm ;

= Area of isosceles = 1/2×b×h.

= 1/2×12×10.

= [ 10 divide by 2 ].

= 1×12×5.

= 60. Ans…

(iii) each of the equal sides is 7.4 cm and the

base is 6.2 cm;

= Area of isosceles = 1/2×b×h.

= 1/2×6.2×7.4.

= [ 7.4 divide by 2].

= 1×6.2×3.7.

= 22.94. Ans…

(iv) perimeter is 11 cm and base is 4 cm.

= Area of isosceles = 1/2×b×h.

= 1/2×4×11.

= 2×11.

= 22. Ans…

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