Question

16
Find
the following products (x^3+3)×4×(9x-2)×2x^2​

Answer 1

Answer:

72x^6-16x^5+216x^3-48x^2

Step-by-step explanation:

first open the first bracket and multiply it with 4

(x^3+3)×4=4x^3+12

and then open second bracket and multiply it with 2x^2

(9x-2)×2x^2=18x3-4x^2

so there is only one multiplication sign is left between

(4x^3+12)×(18x^3-4x^2)

then multiply 4x^3 by (18x^3-4x^2) = 72x^6-16x^5

and then multiply +12 by (18x^3-4x^2)

= 216x^3-48x^2

SO THE answer we got is

= 72x^6-16x^5 + 216x^3-48x^2