Question

16 )Find the greatest 4-digit number which is
exactly divisible by each of 12, T8 and 30​

Answer 1

First we find the LCM of 8,12 and 20.

∴ LCM of given numbers =2×2××3×5=120  

According to given condition , we need a greatest number of 4 -digit which is exactly divisible by 120.

Greatest number of 4-digit =9999  

We divide 9999 by 120 and find the remainder

∴ The required number =9999−39=9960 .

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