Question

16. Find the magnitude and direction of a displacement vector having x and y components of - 5m and 3m, respectively.​

Answer 1

Answer:

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Answer 2

Answer:5.83m, 149°

Explanation:

magnitude = $\sqrt{x^{2} +y^{2} }$

=$\sqrt{(-5^{2} )+(3^{2}) }$

=5.83m

the direction of the displacement vector

Tanθ = y/x

θ = Tan-1 (3/-5)

θ = -30.96°

180° - 30.96°

= 149.04°