16. find the measur of each angles
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Answer:
P=120, Q=120, S=60, R=60
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Sum of the angles of a quadrilateral = 360⁰
given <P = <Q and <R = < S
<P = 2 <R
<R = <P/2
<P + <Q + <R + <S = 360⁰
<P + <P + <P/2 + <P/2 = 360⁰
2<P + 2<P/2 = 360⁰
2<P + <P = 360⁰
3<P = 360⁰
<P = 360/3
<P = 120⁰ = <Q
<R = <P/2
<R = 120⁰/2
<R = 60⁰ = <S
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