Question

16. Find the minimum rate at which fuel must be consumed by a rocket so as to be able
to take off vertically. Given that the total mass at the time of take off is 3000 kg and
the velocity of the fuel expelled is 300 m/s. (g = 9.8 m/s]

(Please help me fast )​

Answer 1

Answer:

We have mass of rocket = 50 kg and mass of fuel = 450 kgThus total mass = 500 kg Exhaust speed of rocket vr = 2 km/s = 2 × 103 m/s Force = mass × gravity ...

Answer 2

Explanation:

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