Question

16. Find the minimum rate at which fuel must be consumed by a rocket so as to be able
to take off vertically. Given that the total mass at the time of take off is 3000 kg and
the velocity of the fuel expelled is 300 m/s. (g = 9.8 m/s]

(Please help me fast please with the correct answer please )​

Answer 1

Answer:

98kg\s

Explanation:  

              Total mass = 3000 kg

               Vr=300m/s

Force= mass * gravity

Force=3000*9.8=29,400

dm\dt =rate of fuel burn

F=Vr*dm\dt

dm/dt=F\Vr=29400\300