Math, asked by puneethkadiyalpccj7x, 11 months ago

16. Find the product of (x - a) (x - b) (x -c), given that the sum a+b+c= 7, ab+bc+ca=0
and abc = -36​

Answers

Answered by ashu3998825
10

Answer:

(x-a)(x-b)(x-c)=x^3 - (a+b+c)x^2

+(ab+bc+ca)x-abc

= x^3 - 7x^2 + (0)x - (-36)

= x^3 -7x^2 +36

Answered by ariepayne1234
2

Answer:

x^3 -7x^2 +36

Step-by-step explanation:

GIVEN:-

a+b+c = 7,

ab+bc+ca = 0

abc = -36

PROOF:-

(x-a)(x-b)(x-c) = x^3 - (a+b+c)^2 + (ab+bc+ca)x - abc

= x^3 - 7x^2 + (0)x -(-36)

= x^3 - 7x^2 +36

hope it will help you

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