Question

16) Find the value of x ,y,z from the following Xx [y+(-6)] = [13x (-19)] + [13xz]​

Answer 1

Answer:

X=0

y=6

z=19

Step-by-step explanation:

X(y-6)=13x(-19+Z)

( y - 6) = 0

y=6

13 ( -19 + z ) =0

-247 + 13z =0

13Z = 247

Z= 247/13

Z = 19

X ( 6 - 6) = 13X ( -19+19)

X(0)= 13X (0)

0=0

X=0

Answer 2

The values are x = 13 , y = - 19 , z = - 6

Given :

$\displaystyle \sf{x \: \times \: [y + ( - 6)] =[13 \times ( - 19)] +[13 \times z] }$

To find :

The value of x , y , z

Concept :

Distributive Property :

For there real numbers a , b , c

$\sf{a \times (b + c) = (a \times b) + (a \times c)}$

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{x \: \times \: [y + ( - 6)] =[13 \times ( - 19)] +[13 \times z] }$

Step 2 of 2 :

Find the value of x , y , z

We apply the Distributive Property

$\sf{a \times (b + c) = (a \times b) + (a \times c)}$

Thus we get

$\displaystyle \sf{x \: \times \: [y + ( - 6)] =[13 \times ( - 19)] +[13 \times z] }$

$\displaystyle \sf\implies x \: \times \: [y + ( - 6)] =13 \times [( - 19) + z]$

Comparing both sides we get

x = 13 , y = - 19 , z = - 6

Correct question : Find the value of x ,y,z from the following x × [y + (-6)] = [13 × (-19)] + [13 × z]

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