Question

16 g of a solute is dissolved in 100 mL of water to form a saturated solution at 25°C. The strength of the solution (in g L-¹), will be equal to​

Answer 1

Answer:

Given mass of NaOH=16 grams → Solute.

Given mass of water = 100 grams → Solvent

Solubility (in g/100g) =

solvent

Mass

×100

=

100

16

×100=16

Solubility of the solution is 16(g/100g)

Weight Percentage =

massofsolution

MassofSolute

×100

(100+16)g

16g

×100

Weight percentage =13.79%