Question

16 g of CH4 is burnt in presence of 64 g oxygen togive CO2 and H20. The mass of CO2 formed is
11g
22 g
44 g
889

Answer 1

Answer:

44g

Explanation:

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Answer 2

Given:

Mass of CH₄ = 16 g

Mass of O₂ = 64 g

To find:

The mass of CO₂ formed

Calculation:

According to the data given the question, the reaction taking placebwill be combustion of methane

    $CH_4+2O_2\longrightarrow CO_2+2H_2O$

Molecular weight of CH₄ = 16 g

No of moles of CH₄ in 16 g is

     $n=\frac{given\ weight}{molecular\ weight} =\frac{16}{16}=1$

Molecular weight of O₂ = 32 g

No of moles of O₂ in 64 g is

     $n=\frac{given\ weight}{molecular\ weight} =\frac{64}{32}=2$

According to the reaction 1 mole of CH₄ and 2 moles of O₂ gives 1 mole of CO₂

Weight of 1 mole of CO₂ = 1(C) + 2(O)

                                         = 12+32 = 44 g

Final answer:

The mass of CO₂ formed is 44 g [Option(a)]