Question

16 g of ice is converted to steam at 100 degree Celsius . find the amount of heat required. ( sp heat water=1cal/g degree Celsius(latent heat at fusion =80cal/g(latent heat of vapour =540cal/g​

Answer 1

Answer:

amount  of heat=m*Lf+m*s*T+m*Lv

=16*80+16*100*1+16*540

=11520cal

Answer 2

Refer Attachment For Explanation!!!