16 g of oxygen gas is enclosed in a 1 dm³ flask at 25°C. Calculate the pressure exerted by the gas, if the molecular mass( molar mass ) of any gas occupies 22.4 litres at S.T.P.
Answers
Answer:
Dear Student,
Please find below the solution to the asked query:
Given mass of oxygen = 16g
Molar mass of Oxygen gas = 32g/mol
No.of moles of Oxygen = 16/32
n = 0.5mol
Given Volume = 1dm3 = 1L = 1 ×10-3m3
Gas constant , R = 8.314JK-1mol-1
T = 298K
Substituting the values in the equation:
P = nRTV
We get, P = 0.5×8.314×2981×10−3
= 1238 × 103Pa
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HERE IS UR ANSWER
for oxygen
Given mass=16
molar mass=32
n=16/32=0.5
given volm=1dm^3=1L=10^-3m^3
R=8.314
T=298K
P=nRTV
P=1238×10^-3Pa