Question

16 g of oxygen has same number of molecules as in
1) 16 g of Co
2) 28 g of N2
3) 14 g of N2
4) 2 g of He
​

Answer 1

Explanation:

28gm of N2 Is the correct answer

Answer 2

3). 14 g of $N_{2}$

Explanation:

Given that,

16 g of oxygen

To find,

16 g of oxygen has a similar no. of molecules as in = ?

Procedure:

Firstly, we will find the number of molecules in 16g of oxygen.

= Mass/Molar mass * Avogadro number($N_{A}$)

= 16/32 * $N_{A}$

= 16/32 * 6.023 * 10^23

= 0.5 * 6.023 * 10^23

Since 14g of Nitrogen contains 0.5 moles, it will also have moles

= 0.5 * 6.023 * 10^23

Thus, number of molecules of $N_{2}$ = 14/28 * 6.023 * 10^23

so,

16g of Oxygen   = 14g of  $N_{2}$

0.5 *  6.023 * 10^23 = 0.5 *  6.023 * 10^23

Hence, option 3 is the correct answer.

Learn more: Find the number of molecules

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