Question

16 g of So, occupies 5.6 litre at STP. Assuming ideal gas nature. The value of x is:
(A) 1
(D) None of these
(B) 2
(C) 3​

Answer 1

Explanation:

1 mole of SOx occupies 22.4 litre at STP.

So 16 g of SOx occupies 5.6 litre at STP.

Hence 16g of SOx is (5.6/22.4) moles =>

16g of SOx =0.25 moles => 1 mole of SOx weighs 16/0.25 g=>64 g. So 32+x(16)=64=>

16x=64-32=32=>x=2. The value of x is 2. Hope it helps you.

Answer 2

Answer:

2

is the correct answer