16 g of SOx occupies 5.6 litres at STP. Assuming ideal gas nature, the value of x is
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HERE IS THE ANS-
NO. OF MOLES = volume of gas at STP/22.4(liters)
= 5.6 / 22.4 =
= 0.25 moles
now ,,
we also know that -
no. of moles = weight in gram/molecular mass
by above --
0.25 = 16/mole. mass
molecular mass = 16/0.25 = 64
so , now we know that the molecular mass of SO2 gas is 64 ..
so, the value of X here is 2...
and the gas is SO2 (SULPHUR DIOXIDE)..
✨HOPE IT HELPS YOU ✨
NO. OF MOLES = volume of gas at STP/22.4(liters)
= 5.6 / 22.4 =
= 0.25 moles
now ,,
we also know that -
no. of moles = weight in gram/molecular mass
by above --
0.25 = 16/mole. mass
molecular mass = 16/0.25 = 64
so , now we know that the molecular mass of SO2 gas is 64 ..
so, the value of X here is 2...
and the gas is SO2 (SULPHUR DIOXIDE)..
✨HOPE IT HELPS YOU ✨
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