Question

16 g oxygen expands at STP isobarically to occupy double of its original volume. The work done during the process will be:

Answer 1

Answer:

32 grams O  

2

​  

=1 mole

16 grams O  

2

​  

=0.5 mole

16×10  

3

 gram =16kg =500 moles of O  

2

​  

(n)

We know that,

W=−nPV, Now we know, At STP, T=273K

W=nRTIn  

V  

1

​  

 

V  

2

​  

 

​  

 

Here n= number of moles =  

32

16000

​  

=500R=1.986 cal

T=273K

V  

1

​  

 

V  

2

​  

 

​  

=2

So, W=500x1.986×273×In2

           =187905 cal

           =187.905 K.cal

Explanation: