Question

16 gm oxygen was expanded at STP to occupy double of its volume. The work done in this process will be in lit- atmosphere.
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Answer 1

Answer:

32 grams O2=1 mole

16 grams O2=0.5 mole

16×103 gram =16kg =500 moles of O2(n)

We know that,

W=−nPV, Now we know, At STP, T=273K

W=nRTInV1V2

Here n= number of moles =3216000=500R=1.986 cal

T=273K

V1V2=2

So, W=500x1.986×273×In2

            =187905 cal

            =187.905 K.cal