16 gram o2 and 14 gram n2 has how many molecules
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Answer:
6.022 x 10^23
Explanation:
32 gm O2 has one avogadro number of molecules(molecular mass of O2 is 32)
hence 16 gm will have half of one avogadro
28 gm N2 will have one avogadro number of molecules(molecular mass of N2 is 28)
hence 14 gm will have half of one avogadro
both together makes one avogadro that is, 6.022X 10^23
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