Question

16 gram of a solute is dissolved in 100 ml of water to form a saturated solution at 25° Celsius . find its strength​ ?

Answer 1

Answer:Given mass of NaOH=16 grams \rightarrow→ Solute.

Given mass of water = 100 grams \rightarrow→ Solvent

Solubility (in g/100g) =\cfrac{Mass\quad }{ solvent}\times 100=

solvent

Mass

​

×100

=\cfrac{16}{100}\times 100=16=

100

16

​

×100=16

Solubility of the solution is 16(g/100g)

Weight Percentage =\cfrac{Mass\quad of \quad Solute}{mass\quad of\quad solution}\times 100=

massofsolution

MassofSolute

​

×100

\cfrac{16g}{(100+16)g}\times 100

(100+16)g

16g

​

×100

Weight percentage =13.79\%=13.79%

Answer 2

Answer:

160 g/L

Explanation:

Mass of Solute: 16g
Volume of Solvent: 100mL = 0.1L

Mass by Volume Percentage
=> 16/0.1
=> 160 g/L