16 gram of methane gas occupies ____ liter at stp
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3
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There really is no need to use the ideal gas law when STP is present. Thus, 16.5 g methane x 1 mole/16 g = 1.03 moles methane. 1.03 moles x 22.4 liters/mole = 23.1 liters (to 3 significant figures).
Answered by
5
Answer:
There really is no need to use the ideal gas law when STP is present. Thus, 16.5 g methane x 1 mole/16 g = 1.03 moles methane. 1.03 moles x 22.4 liters/mole = 23.1 liters (to 3 significant figures).
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