Chemistry, asked by prahlad1234july, 3 months ago

16 gram of methane gas occupies ____ liter at stp​

Answers

Answered by aanurayaprol
3

Answer:

There really is no need to use the ideal gas law when STP is present. Thus, 16.5 g methane x 1 mole/16 g = 1.03 moles methane. 1.03 moles x 22.4 liters/mole = 23.1 liters (to 3 significant figures).

Answered by someoneweir944
5

Answer:

There really is no need to use the ideal gas law when STP is present. Thus, 16.5 g methane x 1 mole/16 g = 1.03 moles methane. 1.03 moles x 22.4 liters/mole = 23.1 liters (to 3 significant figures).

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