Question

16 grams of O2 occipies how much volume?​

Answer 1

Answer:

Explanation:

1 mole of a gas occupy =22.4L volume at STP therefore, 16gO2 gas =0.5 mole of O2 gas will occupy =0.5×22.41=11.2L at STP.

Answer 2

Answer:

1 mole of a gas occupy =22.4L volume at STP therefore, 16gO2 gas =0.5 mole of O2 gas will occupy =0.5×22.41=11.2L at STP