Question

16. How many tiles with dimensions 5 cm and 12 cm will be needed to fit a region whose length
and breadth are respectively:
(i) 100 cm and 144 cm
(ii) 70 cm and 36 cm​

Answer 1

❶ No. of tiles in 100cm and 144cm $\large\leadsto\boxed{\tt\purple{240 \: tiles}}$

❷ No. of tiles in 70cm and 36cm $\large\leadsto\boxed{\tt\purple{42 \: tiles}}$

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• Given:-

Dimension of tiles is 5cm and 12cm

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• To Find:-

Number of tiles needed to fit in region of

100cm and 144cm

70cm and 36cm

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• Solution:-

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1.)

Given that,

Length of the tiles = 5cm

Breadth of the tiles = 12cm

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Therefore,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{Area = length \times breadth}}}$

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➪ $\sf Area = 12 \times 5$

★ $\bf\red{Area = 60 \: cm^2}$

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Also,

Length of the rectangular region = 100cm

Breadth of the rectangular region = 144cm

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Therefore,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{Area = length \times breadth}}}$

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➪ $\sf Area = 100 \times 144$

★ $\bf\red{Area = 14400 \: cm^2}$

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Hence,

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The tiles required to fit in the given region will be,

No. of tiles = Area of the region / Area of the one tile

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➪ $\sf No. \: of \: tiles = \dfrac{14400}{60}$

★ $\large{\bf\pink{No. \: of \: tiles = 240 \: tiles}}$

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2.)

Length of the rectangular region = 70cm

Breadth of the rectangular region = 36cm

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$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{Area = length \times breadth}}}$

➪ $\sf Area = 70 \times 36$

★ $\bf\red{Area = 2520 \: cm^2}$

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Now,

We know the area of 1 tile = 60 cm²

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Therefore,

No. of tiles = Area of the region / Area of the one tile

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➪ $\sf No. \: of \: tiles = \dfrac{2520}{60}$

★ $\large{\bf{\pink{No. \: of \: tiles = 42 \: tiles}}}$

Answer 2

Answer:

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