Question

16. If 1 is the root of the equation x2+bx+1=0 and the equation x2+bx+q=0 has equal roots then the value of q is​

Answer 1

Answer:

value of q is 1

drop some thanx

Answer 2

Answer:

Given equation x

2

+bx+12=0

one root is 2

So, put x=2

4+2b+12=0

2b=−16

b=−8

Now roots of equation x

2

+bx+q=0 are equal

So, D=0

b

2

−4q=0

(−8)

2

−4q=0

4q=64⇒q=16