Question

16. IF (-3,2) is the midpoint of the line joining the points (-6,4) and (x,y),then find the value
of (x,y)​

Answer 1

$\sf\underline{Answer:}$

The value of x and y is 0 ; (x, y) = (0, 0)

$\sf\underline{Explanation:}$

Given, (-3, 2) is the midpoint of the line joining (-6, 4) and (x, y)

→ Using the midpoint formula,

$midpoints = (\frac{ x_{1} + x_{2}}{2} , \frac{ y_{1} + y_{2}}{2})$

$( - 3,2) = (\frac{ - 6 + x}{2} , \frac{4 + y}{2} )$

→ Solving the x-coordinates,

$- 3 = \frac{ - 6 + x}{2 }$

$- 6 = - 6 + x$

$x = 0$

→ Now, y-coordinates

$2 = \frac{4 + y}{2}$

$4 = 4 + y$

$y = 0$

$(x,y) = (0,0)$

Have a good day!