Question

16. If (3,3) be the mid point of A(x, -2) and B(4,y), then find the values of x and y.​

Answer 1

Answer:

${\bold{\therefore x=2}}$

${\bold{\therefore y=8}}$

Step-by-step explanation:

${\bold{\huge{\underline{SOLUTION-}}}}$

• In the given question information given about a line and co-ordinate of mid point of this line is given.

• We have to find the values of x and y.

$\underline \bold{Given : } \\ \implies Coordinate\:of C= (3,3 )\: \: \: \: (Mid \: point \: of \: line \: AB) \\ \implies Coordinate \: of \: A= (x,- 2) \\ \implies Coordinate \: of \:B = (4,y) \\ \\ \underline \bold{To \: Find : } \\ \implies Value \: of \: X= ? \\ \implies Value \:o f \: Y= ?$

• According to given question :

$\bold{By \: Mid \: point \: formula : } \\ \implies x = \frac{ x_{1} + x_{2} }{2} \\ \bold{For \: x \: abscissa : } \\ \implies 3 = \frac{x + 4}{2} \\ \implies 6 = x + 4 \\ \implies x = 6 - 4 \\ \bold{ \implies x = 2} \\ \\ \bold{For \: y \: ordinates : } \\ \implies y = \frac{ y_{1} + y_{2} }{2} \\ \implies 3 = \frac{ - 2 + y}{2 } \\ \implies 6 = - 2 + y \\ \implies y = 6 + 2 \\ \bold{ \implies y = 8}$

Answer 2

ANSWER:-

Given:

If (3,3) be the mid-point of A(x,2) & B(4,y)

To find:

Find the values of x & y.

Solution:

⚫Mid-point is the middle point of any line segment.

⚫Coordinate of C(3,3) is the mid-point.

⚫A(x,-2)

⚫B(4,y)

Therefore,

Using the formula of mid-point is;

For x coordinate, we get;

$= >x = \frac{x1 + x2}{2} \\ \\ = > 3 = \frac{x + 4}{2} \\ \\ = > 6 = x + 4 \\ \\ = > x = 6 - 4 \\ \\ = > x = 2$

And, Again for y coordinate:

$= > y = \frac{y1 + y2}{2} \\ \\ = > 3 = \frac{ - 2 + y}{2} \\ \\ = > 6 = - 2 + y\\ \\ = > y = 6 + 2 \\ \\ = > y = 8$

Hence,

The value of x is 2 &

the value of y is 8

=) (2,8)

Hope it helps ☺️