16. If 3(log 5 - log 3) - (log 5 - 2 log 6)
= 2 - log x, find x.
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3(log 5 - log 3) - (log 5 - 2log 6) = 2 -logx
3log5 - 3log3 - (log 5 - log 6²) = 2 - logx
3log5 - 3log3 - log5 + log6² = 2 - logx
2 log5 + 2 log6 - log3³ = 2 - logx
2 (log5+log6) - log3³ = 2 - logx
2 log30 - log27 + logx = 2
log30² - log27 + logx = 2
log(900/27) + logx = 2
log(100/3) + logx = 2
log(10)² -log3 + log x = 2
2log 10 +log(x/3) = 2
2 + log(x/3) = 2
logx - log3 = 0
logx = log3
x = 3
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