Question

16. If 4 sin 0 - 3 cos 0 = 0 then find: (a) sine (b) cos © (C) sec 0 cosec o.​

Answer 1

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$4 \sin( \theta ) - 3\cos( \theta) = 0 \\ \\ 4 \sin( \theta ) =3 \cos( \theta ) \\ \\ \frac{ \sin( \theta ) }{ \cos( \theta ) } = \frac{3}{4} \\ \\ \tan( \theta ) = \frac{3}{4} \\ \\ \tan(30)° = \frac{3}{4} \\ \theta = 30 °\\ \\ a) \sin(30)° = \frac{1}{2} \\ \\ b) \cos( 30)° = \frac{ \sqrt{3} }{2} \\ \\ c) \sec( 30)° = \frac{2}{ \sqrt{3} } \\ \\ d) \csc(30)° = 2$

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Answer 2

Answer:

4sin(θ)−3cos(θ)=0

4sin(θ)=3cos(θ)

cos(θ)

sin(θ)

=

4

3

tan(θ)=

4

3

tan(30)°=

4

3

θ=30°

a)sin(30)°=

2

1

b)cos(30)°=

2

3

c)sec(30)°=

3

2

d)csc(30)°=2