Question

16. If a, ß are the zeroes of the polynomial f(x) = ax + bx + c, then find -
1/à^+1/b^​

Answer 1

Step-by-step explanation:

a,b are zeroes of polynomial f(x) = ax^2 + bx + c

a+b = - b/a

a.b = c/a

1/a + 1/b = (b + a) /a.b

= -b/a/c/a = -b/a × a/c

= -b/c

Answer 2

HEY MATE YOUR ANSWER IS HERE...

AS WE KNOW

$sum \: of \: zeroes \: = \frac{ - b}{a}$

AND

$product \: of \: zeroes \: = \frac{c}{a}$

NOW ,

$\alpha + \beta = \frac{ - b}{a} - - - eq1$

AND

$\alpha \beta = \frac{c}{a} - - - - - eq2$

NOW WE HAVE TO FIND THE VALUE OF

$\frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \alpha + \beta }{ \alpha \beta }$

NOW PUT THE VALUES FROM EQUATION 1 AND 2

$\frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \frac{ - b}{a} }{ \frac{c}{a} }$

HENCE

$\frac{1 }{ \alpha } + \frac{1}{ \beta } = \frac{ - b}{c}$

THANKS FOR YOUR QUESTION HOPE THIS HELPS

★ KEEP SMILING ☺️✌️ ★